# Line slope calculator 5x+7y=47

**Straight line given by points A[1; 6] and B[8; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.7143x+6.7143

**Canonical form of the line equation:**5x+7y-47 = 0

**Parametric form of the line equation:**

x = 7t+1

y = -5t+6 ; t ∈ R

**Slope:**m = -0.7143

**Slope angle of line: φ =**-35°32'16″ = -0.6202 rad

**X intercept:**x

_{0}= 9.4

**Y intercept:**y

_{0}= q = 6.7143

**Distance line from the origin:**d

_{0}= 5.4636

**The length of the segment AB: |AB| =**8.6023

**Vector: AB =**(7; -5)

**Normal vector: n =**(5; 7)

**Midpoint of the segment AB: M =**[4.5; 3.5]

**Perpendicular Bisector equation:**7x-5y-14 = 0

**Vector OA = (1; 6) ; |OA| = 6.0828**

**Vector OB = (8; 1) ; |OB| = 8.0623**

**Scalar product OA .OB = 14**

**Angle ∠ AOB = 73°24'46″ = 1.2813 rad**